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Equation of right bisector = equation of a point at the middle of the line segment.
Let the point P be (x,y) on line AB
x=(1+5)/2=3
y=(2-6)/2=-2
slope of whose co ordinates are given=(-6-2)/(5-1)
=-2
slope of line whose co ordinates are given* slope of line AB=-1(rule)
therefore, -2*slope of line AB=-1
slope of line AB=1/2
equation of line AB
y-y1=slope ( x-x1)
y-(-2)=1/2(x-3)
2(y+2)=x-3
2y+4=x-3
2y-x=-7(ans)
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Morziul:
right now the option not showing, but i will mark u,,,,thank u for ur kind respond on my question ：-）
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