Question

plz help me with this guys​

Answer 1

Question:

• A die is thrown once, then what is the probability of getting an odd non - prime number ?
• (A)1/1
• (B)1/2
• (C)1/3
• (D)1/4

Answer:

$\large\bold\red{\frac{1}{6}}$

Step-by-step explanation:

Given,

A die is thrown once,

Therefore,

All Possible outcomes = { 1,2,3,4,5,6 }

Total number of possible outcomes = 6

Odd non - primes = { 1 }

Total Number of favourable Outcome = 1

Therefore,

Probability = 1/6

Hence,

All Options Provided are wrong.

Answer 2

Question :-----

• A dice is thrown once, find the probability of getting and odd non -Prime number ?

Solution :------

Since when dice is thrown once, Total possible outcomes will be = { 1 , 2, 3 ,4 , 5 ,6}

Now , first we will understand what is a odd Non - Prime Number ?

Odd number :---- An odd number is an integer which is not a multiple of 2 or A number that when divided by 2, leaves a remainder (of 1) ....

So, our Possible outcomes will be = 1, 3 and 5 .

Now, let see what is a Non - Prime Number ?

Non - Prime Number :--- Nonprime numbers are integers that are not prime numbers, i.e. zero (0), one (1), minus one (–1) ...

So our Possible outcome will be = 1 only .

Now, we get, our Possible outcome of Odd Non - Prime Number is = 1

so,

Required Probability = (favorable outcomes/ total number of possible outcomes. )

→ Probability = 1/6 (Ans)