Plz help me with this one.
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1
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ANSWER
Since, a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−bc−ca−ab)
Given, a+b+c=0
∴a
3
+b
3
+c
3
−3abc=0
∴a
3
+b
3
+c
3
=3abc
Option B is correct.
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