plz help me with this question
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Here s your answer..ok mate..
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ACD
tan45=h+8/x
x=h+8.....(1)
ABE
tan30=h/x
1/√3=h/x+8.......(from 1)
h+8=h√3
8==h√3-h
8=h(√3-1)
h=8/(√3-1)
h=8× (√3+1)/(√3-1)×√3+1)
h=8√3+8/2
h=8×1.73+8/2
h= 10.92m
total height =10.92+8=18.92m
tan45=h+8/x
x=h+8.....(1)
ABE
tan30=h/x
1/√3=h/x+8.......(from 1)
h+8=h√3
8==h√3-h
8=h(√3-1)
h=8/(√3-1)
h=8× (√3+1)/(√3-1)×√3+1)
h=8√3+8/2
h=8×1.73+8/2
h= 10.92m
total height =10.92+8=18.92m
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