Plz help me with this question. i have been trying it since very long. steps also plz
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⇒ ∠ROP + ∠POT + ∠TOS = 180°
⇒ Linear pair
⇒ 4b + 75° + b = 180°
⇒ 5b = 180° – 75°
⇒ 5b = 105°
⇒ b = ¹⁰⁵/₅
⇒ b = 21°
Let's substitute this value in 4b and b :
➻ ∠ROP : 4b = 84°
➻ ∠TOS : b = 21°
⇒ ∠POT + ∠TOS = ∠ROQ
⇒ Vertically opp angles
⇒ 75° + b = 2c
⇒ 75° + 21° = 2c
⇒ 96° = 2c
⇒ ⁹⁶/₂ = c
⇒ c = 48°
On substituting :
➻ ∠ROQ : c = 48°
⇒ ∠POR = ∠QOS
⇒ Vertically opp angles
⇒ 4b = a
⇒ 4 × 21° = a
⇒ a = 84°
Now, we get :
➻ ∠POR : a = 84°
_____________________
∴ The value of a, b, c are 21°, 84° and 48° respectively.
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