Question

Plz help me with this question. I will mark u brainiest. Plz.

Answer 1

Answer:

➡️option d

$y = \sqrt{x + \sqrt{x + \sqrt{x + \sqrt{x + ... \infty } } } }$

$y²=x+y$

$differen</strong><strong>t</strong><strong>iation \: on \: both \: sides$

$2y \frac{dy}{dx} =1+ \frac{dy}{dx} [</strong><strong>/tex]</strong></p><p></p><p></p><p></p><p><strong>[tex] \frac{dy}{dx} = \frac{1}{2y - 1}$