Question

plz help me with this question ...
plz anwer with explanation...
unnecessary answers will be reported.... ​

Answer 1

$Given \: Total \: questions \:attempted = 50$

$Let \: number \: of \: questions \:attempted$

$correctly = x$

$number \: of \: questions \:attempted$

$incorrectly = (60-x)$

$Number \: marks \: allotted \: each \: correct$

$answer = 3$

$Number \: marks \: loses \:for \: each /tex]</p><p>[tex] incorrect \: answer = 1$

$Total \:score = 106 \: (given)$

$\implies 3x - 1(10-x) = 106$

$\implies 3x - 10 + x = 106$

$\implies 4x = 106 + 10$

$\implies 4x = 116$

$\implies x = \frac{116}{4}$

$\implies x = 29$

Therefore.,

$\red{number \: of \: questions \:attempted}$

$\red{correctly}\green { = 29}$

••♪

Answer 2

• Correct answer =x =39

• Incorrect answer = [50-x]

= [50-39]

= 11 incorrect answer

Explanation:-

• Total questions she attempted=50

• Let the correct answer be x
• Let the incorrect answer be 50-x
• marks given for every correct answer= 3
• So , total marks scored by correct answer= 3×x = 3x
• marks given for every incorrect answer = -1

=} 3x+(-1)(50-x) = 106

=} 3x-50+x=106

=} 3x+x=106+50

=} 4x=156

=} x= 156/4

=} x= 39