plz help me with this to earn 20 points
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Answer:
as all the sides are equal
Step-by-step explanation:
question is for 12 points....
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Step-by-step explanation:
given: in the triangle ABC ; AB = BC and AD = DC
TPT : ∠ADE=90 and AE=EC
proof:
in the triangle ADB and CDB;
AB = BC (given)
AD = CD (given)
and BD is common.
therefore by SSS congruency ; △ADB≅△CDB
therefore by CPCT congruency property;
∠ABD=∠CBD ............(1)and ∠ADB=∠CDB=1802=90
∠ADE=∠CDB [vertically opposite angles]∠ADE=90 deg
now in the triangles ABE and CBE;
AB=BC [given]∠ABE=∠CBE [from eq(1)]BE is common.therefore by SAS congruency△ABE≅△CBE
and by cpct, AE = EC.
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