Question

plz help mee plz I will make brainest .​

Answer 1

Answer:

The answer is 0 cos 0

Step-by-step explanation:

Please make me brainliest

Answer 2

Answer:

Proof required

Step-by-step explanation:

Let us do Expansion of LHS

=> cosec²Ф - 2cosecФcotФ + cot²Ф

=> 1 + 2cot²Ф - 2cosecФcotФ

=> 1 + $\frac{2cos^2x}{sin^2x}$ - $\frac{2cosx}{sin^2x}$  ( let Ф = x for some time)

=> $\frac{sin^2x + cos^2x + cos^2x - 2cosx}{sin^2x}$

=> $\frac{1 - 2cosx + cos^2x}{sin^2x}$

=> $\frac{(1 - cosx)^2}{1 - cos^2x}$

=> $\frac{(1 - cosx)(1 - cosx)}{(1 - cosx)(1 + cosx)}$

=> $\frac{1 - cosx}{1 + cosx}$  =  RHS

Hence proved...

Mark it as brainliest dear..