Question

plz help meee......​

Answer 1

${ \bold{ \green{ \underline{ANSWER : }}}}$

${ \bold{ \underline{REACTION : }}}$

${ \bold{ \pink{ C_{3} H_{8} + 3O_{2} \: \: -> 3 CO_{2} + 4 H_{2} }}}$

${ \bold{ \red{Moles \: \: of \: \: propane = \frac{36}{44} }}}$

${ \bold{Required \: \: moles \: \:o f \: O_{2} \: \: for \: \: 1 \: \: mol \: \: propane = 3 }} \\ \\ { \bold{Required \: \: moles \: \: of \: O_{2} \: \: for \: \: \frac{36}{44} \: \: mol \: \: propane = 3 \times \frac{36}{44} =2.45 \: mol }}$

${ \bold{ \boxed{ \pink{Required \: \: mol \: \: of \: \: O _{2} = 2.45 \: mol}}}}$

Answer 2

REACTION

${ \bold{ \orange{ C_{3} H_{8} + 3O_{2} \: \: -> 3 CO_{2} + 4 H_{2} }}}$

${ \bold{ \blue{Moles \: \: of \: \: propane = \frac{36}{44} }}}$

${ \bold{Required \: \: moles \: \:o f \: O_{2} \: \: for \: \: 1 \: \: mol \: \: propane = 3 }} \\ \\ { \bold{Required \: \: moles \: \: of \: O_{2} \: \: for \: \: \frac{36}{44} \: \: mol \: \: propane = 3 \times \frac{36}{44} =2.45 \: mol }}$

${ \bold{ \boxed{ \pink{Required \: \: mol \: \: of \: \: O _{2} = 2.45 \: mol}}}}$