Question

plz help meeeee. qno. 23. give ans in pic

Answer 1

$\textbf{Answer:}$

We have,

$x = 2y + 6 \\ \\ = > x + ( - 2y) + ( - 6) = 0 \\ \\ ∴ \: \: {x}^{3} + ( - 2y {)}^{3} + ( - 6 {)}^{3} = 3x( - 2y)( - 6) \\ \\ = > {x}^{3} - 8 {y}^{3} - 216 = 36xy \\ \\ ∴ \: {x}^{3} - 8 {y}^{3} - 36xy - 216 = 0$

$\textbf{Hope it helps you!}$