Plz help mememeemee!!!!
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Given that (x + a) is the factor,
So, x = -a
====================
By Remainder Theorem,
2x^2 + 2ax + 5x + 10 = 0
2(-a)^2 + 2a(-a) + 5(-a) + 10 = 0
2a^2 - 2a^2 - 5a + 10 = 0
-5a + 10 = 0
10 = 5a
10/5 = a
2 = a
i hope this will help you
(-:
So, x = -a
====================
By Remainder Theorem,
2x^2 + 2ax + 5x + 10 = 0
2(-a)^2 + 2a(-a) + 5(-a) + 10 = 0
2a^2 - 2a^2 - 5a + 10 = 0
-5a + 10 = 0
10 = 5a
10/5 = a
2 = a
i hope this will help you
(-:
Shiifa:
Oh lmao tysm how can i be so duumbbb lol
Answered by
6
Hey!
[ Refer the attachment ]
a = 2
• It is given that x + a is the factor , so if we divide the polynomial we get zero as resultant.
here , by dividing we get ( 10 - 5a )
So, we equate the remainder by 0.
[ Refer the attachment ]
a = 2
• It is given that x + a is the factor , so if we divide the polynomial we get zero as resultant.
here , by dividing we get ( 10 - 5a )
So, we equate the remainder by 0.
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