Question

Plz help only awnser not ur suggestion

Answer 1

Answer:

we know that

a^3 - b^3 = (a - b) (a^2 + ab + b^2)

first term would be

(x^a/x^b)^(a^2+ab+b^2)

={ (x^(a - b)}^{a^2+ab+b^2)

= x^{(a - b)(a^2 + ab + b^2)

= x^(a^3 - b^3)

similarly second term will be

x^(b^3 - c^3)

thir term would be

x^(c^3 - a^3)

since the three terms are in multiplication, the exponents would add up.

so the expression is equal to

x^(a^3 - b^3 + b^3 - c^3 + c^3 - a^3)

= x^0

= 1