Physics, asked by nandamudashi129, 10 months ago

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Answered by ankushsaini23
0

Answer:

Question:-3

[a] (i) He should use a concave mirror, as it forms a real image on the same side of the mirror.

(ii) Object distance, u=-12cm Image distance, v=-48 cm Magnification, m=-v/u=-(-48)/(-12)=-4 The minus sign in magnification shows that the image formed is real and inverted.

(iii) The image is formed at a distance of 35 cm from the object.

(iv) In this case, the image is formed beyond the center of curvature. This image is real, inverted and enlarged.( diagram in attachment)

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Answered by ankushsaini23
1

Answer:

Question:-3

[a] (i) He should use a concave mirror, as it forms a real image on the same side of the mirror.

(ii) Object distance, u=-12cm Image distance, v=-48 cm Magnification, m=-v/u=-(-48)/(-12)=-4 The minus sign in magnification shows that the image formed is real and inverted.

(iii) The image is formed at a distance of 35 cm from the object.

(iv) In this case, the image is formed beyond the center of curvature. This image is real, inverted and enlarged.( diagram in attachment)

  • hope it helps you...
  • please mark it as a brainlist answer...
  • also please rate thanks and follow me...
  • stay home STAY SAFE...
Attachments:
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