Math, asked by Mehak2piyusha, 18 days ago

plz help solve the question​

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Answered by MasterDhruva
22

Solution :-

In the picture attached in the question, we are given with an equation that consists of constanta and variables. We are given a variables named x two times. As the both variables are same, we can conclude that both the values are same. The given equation is,

\sf \leadsto \dfrac{\dfrac{x}{4} - \dfrac{3}{5}}{\dfrac{4}{3} - 7x} = \dfrac{-3}{20}

As we know that, in all the equations there should be an solution to be given in the question which is also provided yo is in this question. The answer provided to us is -3/20. To find the value of the variable x, we use the cross multiplication method.

\sf \leadsto 20 \bigg( \dfrac{x}{4} - \dfrac{3}{5} \bigg) = -3 \bigg( \dfrac{4}{3} - 7x \bigg)

\sf \leadsto \dfrac{20x}{4} - \dfrac{60}{5} = \dfrac{-12}{3} + 21x

\sf \leadsto \dfrac{100x - 240}{20} = \dfrac{-12 + 63x}{3}

Again, cross multiply the numbers.

\sf \leadsto 3 (100x - 240) = 20 (-12 + 63x)

\sf \leadsto 300x - 720 = -240 + 1260x

\sf \leadsto 300x - 1260x = -240 + 720

\sf \leadsto -960x = 480

\sf \leadsto x = \dfrac{480}{-960}

\sf \leadsto x = \dfrac{1}{-2}

\sf \leadsto \dfrac{-1}{2}

Therefore, the value of x is -½.

Answered by Anonymous
26

Answer:

Question :-

\mapsto \bf \dfrac{\dfrac{x}{4} - \dfrac{3}{5}}{\dfrac{4}{3} - 7x} =\: \dfrac{- 3}{20}

To Find :-

\mapsto What is the value of x.

Solution :-

\mapsto\: \: \sf\bold{\purple{\dfrac{\dfrac{x}{4} - \dfrac{3}{5}}{\dfrac{4}{3} - 7x} =\: \dfrac{- 3}{20}}}

\longrightarrow \sf \dfrac{\dfrac{5x - 12}{20}}{\dfrac{4 - 21x}{3}} =\: \dfrac{- 3}{20}

\longrightarrow \sf \bigg(\dfrac{5x - 12}{20}\bigg) \times \bigg(\dfrac{3}{4 - 21x}\bigg) =\: \dfrac{- 3}{20}

\longrightarrow \sf \bigg(\dfrac{3(5x - 12)}{20(4 - 21x)}\bigg) =\: \dfrac{- 3}{20}

\longrightarrow \sf \bigg(\dfrac{15x - 36}{80 - 420x}\bigg) =\: \dfrac{- 3}{20}

\small\bigstar\: \bf{By\: doing\: cross\: multiplication\: we\: get\: :-}

\longrightarrow \sf 20(15x - 36) =\: - 3(80 - 420x)

\longrightarrow \sf 300x - 720 =\: - 240 + 1260x

\longrightarrow \sf 300x - 1260x =\: - 240 + 720

\longrightarrow \sf - 960x =\: 480

\longrightarrow \sf x =\: \dfrac{48\cancel{0}}{- 96\cancel{0}}

\longrightarrow \sf x =\: \dfrac{48}{- 96}

\longrightarrow \sf x =\: \dfrac{\cancel{24}}{- \cancel{48}}

\longrightarrow \sf x =\: \dfrac{\cancel{2}}{- \cancel{4}}

\longrightarrow \sf\bold{\red{x =\: \dfrac{1}{- 2}}}

{\small{\bold{\underline{\therefore\: The\: value\: of\: x\: is\: \dfrac{1}{- 2}\: .}}}}

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