plz help Someone this is the trigonometry questions
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let us assume that (A-B) as θ
let assume that (A+B) as θ₁
so sin(A-B) = sin θ
and cos(A+B) = cosθ₁
sinθ = 1/2
sin θ will be 1/2 when θ = 60°
cosθ₁ will be 1/2 when θ₁ = 30°
so therefore
(A -B) = 60°
(A+B) = 30°
by the process of elimination we get
2 A = 90°
so A = 45°
A + B = 60°
B = 60 -45
B = 15°
so A = 45° and B = 15°
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