Math, asked by ginevra2194, 1 year ago

Plz Help!!
State all algebraic identities.

Answers

Answered by Anonymous
3

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In total there are 10 algebraic identities those are -

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 {(x + y)}^{2} =  {x}^{2} + 2xy +  {y}^{2}

 {(x - y)}^{2} =  {x}^{2} - 2xy +  {y}^{2}

(x + y)(x - y) =  {x}^{2} -  {y}^{2}

(x + a)(x + b) =  {x}^{2} + (a + b)x + (a \times b)

 {(x + y + z)}^{2} =  {x}^{2} +  {y}^{2} +  {z}^{2} + 2xy + 2yz + 2zx

 {(x + y)}^{3} =  {x}^{3} +  {y}^{3} + 3xy(x + y)

 {(x - y)}^{3} =  {x}^{3} - 3 {x}^{2}y + 3x {y}^{2} -  {y}^{2}

 {x}^{3} + y {}^{3} +  {z}^{3} -  3xyz = (x + y + z)( {x}^{2} +  {y}^{2} +  {z}^{2} - xy - yz - zx)

 {x}^{3} +  {y}^{3} = (x + y)( {x}^{2} - xy +  {y}^{2})

 {x}^{3} -  {y}^{3} = (x  - y)( {x}^{2} + xy +  {y}^{2})

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Answered by Anonymous
0

Answer:

  1. (a+b)2=a2+b2+2ab
  2. (a-b)2= a2-2ab+b2
  3. (a2-b2)=(a+b)(a-b)
  4. (x+a) (x+b)=x2+(a+b)x+ab
  5. (x+y+z)=x2+y2+z2+2xy+2xz+2yz
  6. (a+b)3=a3+b3+3ab+(a+b)
  7. (a-b)3=a3-b3-3ab(a-b)

Step-by-step explanation:

hope this is helpull

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