plz help this kid_______
plz just tell me how 0 came as the answer?
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The question is wrong it should be log(2/k) + log(3/k)-log(6/k^2)=0
Step-by-step explanation:
Here we use the identity that log(A)+log(B)=log(A*B)
Therefore log(2/k)+log(3/k)=log(6/k^2)
Here log(6/k^2)-log(6/k^2)=0
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