Math, asked by dharti51, 11 months ago

plz.... help to give answer ....for both questions ​

Attachments:

Answers

Answered by Anonymous
0

first answer is 3

.....please follow me

Answered by GoKuRocxx
0

Answer:

1-\sqrt{3}

2-\frac{\left(5-\sqrt{2}\right)\sqrt{5+\sqrt{2}}-\sqrt{5}\cdot \:23-\sqrt{2}\cdot \:23}{23}

Step-by-step explanation:

First:

⇒√300

⇒√100*3

⇒√10²*3

⇒10*√3

→ Rationalising factor is √3

Second:

⇒1/{√5+(√2)}*{{√5-(√2)}/{√5-(√2)}

\sqrt{5}=\frac{\sqrt{5}\cdot \:23}{23},\:\sqrt{2}=\frac{\sqrt{2}\cdot \:23}{23} ..........convert

\frac{\left(5-\sqrt{2}\right)\sqrt{5+\sqrt{2}}}{23}-\frac{\sqrt{5}\cdot \:23}{23}-\frac{\sqrt{2}\cdot \:23}{23}

\frac{\left(5-\sqrt{2}\right)\sqrt{5+\sqrt{2}}-\sqrt{5}\cdot \:23-\sqrt{2}\cdot \:23}{23}............{\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}}-used

...

It may HELP!

Similar questions