Question

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Answer 1

$\bigstar$ Given:-

The Vividh Bharati station of All India. Radio, Delhi, broadcasts on a frequency of 1,368 kHz (kilo hertz)

$\bigstar$ To Find:-

The wavelength of the electromagnetic radiation emitted by transmitter

Which part of the electromagnetic spectrum does it belong to

$\bigstar$ Solution:-

We know that

$\red{\sf \longrightarrow \lambda=\dfrac{c}{v}}$

Here;

λ = wavelength

c = speed of light in vacuum

v = frequency

Units;

λ = metre (m)

c = m/s

v = Hz

According to the question:

We are asked to find the wavelength of the electromagnetic radiation emitted by transmitter

Therefore;

We must find "λ"

Given that:

The Vividh Bharati station of All India. Radio, Delhi, broadcasts on a frequency of 1,368 kHz (kilo hertz)

We know that!;

kilo (k) = 10³

Hence:

v = 1368 kHz = 1368 x 10³ Hz

We know that;

c = 3 x 10⁸ m/s

Substituting the values

We get

$\blue{\sf \longrightarrow \lambda=\dfrac{3 \times 10^{8}}{1368 \times 10^{3}} \ m}$

On further simplification;

We get

$\green{\sf \longrightarrow \lambda=0.0021929 \times 10^{5} \ m}$

Hence,

$\orange{\sf \longrightarrow \lambda=219.29 \ m}$

On approximation

We get,

$\pink{\sf \longrightarrow \lambda \approx 219.3 \ m}$

Hence

$\star$ Wavelength = 219.3 m

Therefore,

It belongs to "Radio waves region" of the electromagnetic spectrum

Answer 2

Answer:

Wavelength =λ

frequency = ν = 1,368 kHZ 

     c = speed of light =v×λ

   λ=c/λ=3×108/1368×103

     = 219 meters

It belongs the far infrared region or radio wave region.

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