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✴ The ages of Sonu and monu are in ratio 5:7. If 9 years ago,the age of Sonu would have been twice the age of monu. Find their ages .⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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✒ The present ages of Sonu is 7 years and Monu is 5 years.⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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The ages of Sonu and monu are in ratio 5:7.
9 years ago,the age of Sonu would have been twice the age of monu.
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The present ages of Sonu and Monu.
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Let the present age from x .
According to the question,
⭐ The ages of Sonu and monu are in
ratio 5:7.⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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The present age of Monu = 5x
The present age of Sonu = 7x⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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⭐ 9 years ago,the age of Sonu would have been twice the age of monu.
9 years ago Monu's age = 5x - 9
Monu's age 9 years younger = 7x-9
According to the given condition; ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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Our equation will be => 5x - 9 = 2 (7x -9 )
Solving ; 5x - 9 = 2 ( 7x - 9 )
➝ 5x - 9 = 2 ( 7x - 9 )
➝ 5x - 9 = 14 x - 18
➝ 5x - 14x = - 18 + 9
➝ 9 x = 9
➝ x =
➝ x = 1
We Considered;
The present age of Monu ;
=> 5x = 5 × 1 = 5 years
The present age of Sonu ;
=> 7x = 7 × 1 = 7 years.
➡ Hence, Now Monu is 5 years old & Sonu is 7 years old.
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