Question

plz help users !!!!!????? ​

Answer 1

Answer:-

$\red{\bigstar}$ Final velocity acquired $\large\leadsto\boxed{\rm\purple{1.6 \: m/s}}$

• Given:-

Mass of the body = 50kg

Initially at rest.

Force acting on it = 20 N

Time = 4 sec.

• To Find:-

Speed acquired by the body.

• Solution:-

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{F = ma}}}$

where,

F = force

m = mass of the body

a = acceleration

Also,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{a = \dfrac{v}{t}}}}$

where,

a = acceleration

v = final velocity

t = time

Therefore, the final formula:-

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{F = m \times \dfrac{v}{t}}}}$

• Substituting in the Formula:-

→ $\sf 20 = 50 \times \dfrac{v}{4}$

→ $\sf v = \dfrac{20 \times 4}{50}$

→ $\sf v = \dfrac{2 \times 4}{5}$

→ $\sf v = \dfrac{8}{5}$

→ $\large{\tt\red{v = 1.6 \: m/s}}$

Therefore,the final velocity it will acquire is 1.6 m/s.

Further, finding the acceleration:-

• Applying 1st Equation of motion:-

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{v = u + at}}}$

where,

v = final velocity

u = initial velocity

a = acceleration

t = time

• Substituting in the values:-

→ $\sf 1.6 = 0 + a \times 4$

→ $\sf 1.6 = a \times 4$

→ $\sf a = \dfrac{1.6}{4}$

→ $\large{\tt\red{0.4 \: m/s^2}}$

Answer 2

refer the attachment :)