Question

plz help with this question. ​

Answer 1

Answer:

k=3

Step-by-step explanation:

2x²+kx-2=0

when x=-2

2*(-2)²+k*(-2)-2=0

8-2k-2=0

6=2k

k=3

Answer 2

$\sf \: p(x) = 2x² + kx - 2 = 0 \\ \\ \sf→p(2) = 2(2)² + k(2) - 2 = 0 \\ \\ \sf→2×4 + 2k - 2 = 0 \\ \\ \sf→6+2k = 0 \\ \\ \sf→2k = -6 \\ \\ \pink{\mathcal{\boxed{\sf→k = -3}}}$

I HOPE IT HELPS.