plz help with this question . Q1
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Answer:
60% of oxygen and 40% of boron
Explanation:
Mass of compound = 0.24 g,
mass of boron = 0.096 g
percentage of boron in the compound = mass of boron / mass of compound * 100
= 0.096/0.24 * 100 = 40%
mass of oxygen = 0.144 g again, mass of compound = 0.24 g
percentage of oxygen in compound = mass of oxygen/mass of of compound * 100
= 0.144/0.24 * 100 = 60%
thus, the percentage of oxygen and boron in the compound is 60% and 40% respectively
hope it helps :)
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