Question

plz help with this question . Q1​

Answer 1

Answer:

60% of oxygen and 40% of boron

Explanation:

Mass of compound = 0.24 g,

mass of boron = 0.096 g

percentage of boron in the compound = mass of boron / mass of compound * 100

= 0.096/0.24 * 100 = 40%

mass of oxygen = 0.144 g again, mass of compound = 0.24 g

percentage of oxygen in compound = mass of oxygen/mass of of compound * 100

= 0.144/0.24 * 100 = 60%

thus, the percentage of oxygen and boron in the compound is 60% and 40% respectively

hope it helps :)