plz I don't know someone help me plz the 6th one and which one I circled
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Here's your answer please mark me as brainliest
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Hii,
The answer to this question is
(3/2)^-6 × (3/2)^2×5 = (3/2)^m+2
=> (3/2)^-6+10 = (3/2)^m+3 [on multiplication powers r added]
=> (3/2)^4 =(3/2)^m+3
As bases r same......on equating
=> 4 = m+2
=> 4-2 = m
=> 2 = m
Therefore, m = 2
Hope this answer is helpful
The answer to this question is
(3/2)^-6 × (3/2)^2×5 = (3/2)^m+2
=> (3/2)^-6+10 = (3/2)^m+3 [on multiplication powers r added]
=> (3/2)^4 =(3/2)^m+3
As bases r same......on equating
=> 4 = m+2
=> 4-2 = m
=> 2 = m
Therefore, m = 2
Hope this answer is helpful
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