Plz I’m in immediate need for the answer
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According to Kirchhoff's junction law
l1+I2=l3. =>eq1
according to Kirchhoff's Loop law
from ABCFA (1st Loop)
5(I1)-12+2(l3)=0.
from eq1
7(l1)-12+2(l2)=0. =>eq2
from CFEDC (2nd Loop)
2(l3)+3(l2)-6=0
from eq1
2(l1)+5(l2)-6=0. =>eq3
from eq2 &eq3
l1=48/31A
l2=18/31A
l3=66/31A
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