plz i need help to solve this math
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for complementary subtract from 90 degrees
90-28=62
90-30=60
90-67=23
90-(x+5)=90-x-5=85-x
for supplementary subtract from 180 degrees
180-120=60
180-147=33
180-(x+30)=180-30-x=158-x
90-28=62
90-30=60
90-67=23
90-(x+5)=90-x-5=85-x
for supplementary subtract from 180 degrees
180-120=60
180-147=33
180-(x+30)=180-30-x=158-x
shamim47:
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