Math, asked by Aditi2622, 1 year ago

plz I need the and right now

Attachments:

rakeshmohata: a =5 : B = 2root3
kushalankur09p5h135: correct bro
Aditi2622: my a is 5 but my b is not coming 2 root 3

Answers

Answered by Anonymous
3
Hey ^_^

[√3+√2 ] ÷ [ √3 - √2] = a+b√2

(√3+√2 × √3+√2 ) ÷ (√3 -√2 )(√3 +√2)

(√3+ √2)^2 ÷ (√3)^2 - (√2)^2

(3+ 2+2√6 ) ÷ 3 - 2

[5 + 2√6 ] ÷ 1

5+ 2√6

Hence ,
a = 5
b = 2

As it's in the form of a+b√6

✌Hope this helps

Aditi2622: that was helpful
Aditi2622: thanx
Anonymous: My pleasure ^_^
Answered by rakeshmohata
2

 \frac{ \sqrt{3} +  \sqrt{2}  }{ \sqrt{3} -  \sqrt{2}  }  =  \frac{( \sqrt{3}   +   \sqrt{2} )( \sqrt{3}  +  \sqrt{2} )}{ (\sqrt{3}) ^{2}  -  { (\sqrt{2}) }^{2}  }  \\  = ( {( \sqrt{3}  )}^{2}  +  {( \sqrt{2} )}^{2}  + 2. \sqrt{3} . \sqrt{2} ) \div (3 - 2) \\  = 3 + 2 + 2 \sqrt{3} . \sqrt{2}  = 5 + 2 \sqrt{3} . \sqrt{2}  \\  \\ comparing \: with \: a + b \sqrt{2}  \: we \: get \\ a = 5 \:  \: and \:  \: b = 2 \sqrt{3}
Hope this is ur required answer

Proud to help you

Aditi2622: well that was helpful
Aditi2622: thanks
rakeshmohata: welcome.. Mera फर्ज़ tha
rakeshmohata: thnx for brainliest
Aditi2622: ^_^
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