plz I need the answer for both the question
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(2) 27a³+b³+8c³-18abc
using a³+b³+c³-3abc
27a³+b³+8c³-18abc=(3a)³+(b)³+(2c)³-3*3a*b*2c
…(3a+b+2c)³ Ans
using a³+b³+c³-3abc
27a³+b³+8c³-18abc=(3a)³+(b)³+(2c)³-3*3a*b*2c
…(3a+b+2c)³ Ans
Answered by
1
hope this helps you. Any doubt then ask
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