Question

Plz I need the answer quickly

Answer 1

Hi friend,

Here's your answer,

In ∆APD and ∆BPC,
Ang.PAD=Ang.PCB [Alternate angles]
Ang.PDA=Ang.PBC [Alternate angles]
Ang.APD=Ang.BPC [Vertically opposite angles]


Therefore,
∆APD is congruent to ∆BPC

AP=PC
[Corresponding Parts of Congruent Triangles]
PD=BP
[Corresponding Parts of Congruent Triangles]

Therefore,
AP/PD=PC/BP


Hence, proved.




Hope it helps!!!!

#yashankΠsingh