PLZ I need these
Hey guys thanks for answering the first one but could answer 2 to4
2) find the slope of a line goes through (3,7) and (-2,10).
3) the equation of a line is y=6x. Write the equation of a line that is perpendicular to it.
4) The equation of a line isy=3x+7. change the equation so that it is porportional .
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it's 2nd answer for you
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2) x1, y1 = 3,7
x2, y2 = -2,10
slope (m) = y2-y1/ x2-x1
= 10- 7/ -2- 3
=3/-5
3) y= 6x => slope = 6
we know ,
m1*m2 = -1
6*m2 = -1
m2 = -1/6
:. the equation => y = -1/6x
4) I think I can't answer this ..SORRY !
x2, y2 = -2,10
slope (m) = y2-y1/ x2-x1
= 10- 7/ -2- 3
=3/-5
3) y= 6x => slope = 6
we know ,
m1*m2 = -1
6*m2 = -1
m2 = -1/6
:. the equation => y = -1/6x
4) I think I can't answer this ..SORRY !
Princesingh786:
Hlw
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