Math, asked by chucki2761, 1 year ago

Plz.. I need ur help

For what values of k does the quadratic equation 4x2 -12x -k =0 have no real roots??


Ria6344123: ans is -9
chucki2761: How?
Ria6344123: iv solved it now...take a look ...

Answers

Answered by Ajay1291
12

hello friend

b²-4ac

put the value

144-4(4)(k)

144+16k

16k=-144

k=-144/16

k=-9

Answered by DelcieRiveria
16

Answer:

The given quadratic equation have no real roots if k is less than -9.

Step-by-step explanation:

The given quadratic equation is

4x^2-12x-k=0

A quadratic equation ax^2+bx+c=0 have no real roots if its discriminant is less than 0.

b^2-4ac<0

(-12)^2-4(4)(-k)<0

144+16k<0

16k<-144

k<\frac{-144}{16}

k<-9

Therefore, the given quadratic equation have no real roots if k is less than -9.

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