Question

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Answer 1

$\huge{\mathfrak{Heya\:buddy}}$

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$\huge\sf{Answer}$

${\boxed{note = > the \: exterior \: angle \: of \: a \: triangle \: is \: equal \: to \: the \: sum \: of \: interior \:opp. \:triangle}}$


$the \: exterior \:angle \: = 110$

$let \: the \: ratio \:of\: interior \: angle \: be \: 2x \: and \: 3x$

$110 = 2x + 3x \\ 110 = 5x \\ \frac{110}{5} = x \\ 22 = x$

$putting \: the \: value \: of \: x \: in \: 2x \: and \: 3x$

$so \: the \: req. \: angles \: will \: be = > \\ 2(22) = 44° \\ 3(22) = 66°$

$so \: the \: two \: angles \:are \: 44° \: and \: 66°$

${\boxed{the \:sum \: of \: angles \: of \: triangle \: is \: 180°}}$

$let \: the \: third \: angle \: be \: x \\ 44° + 66° + x = 180° \\ 110° + x = 180° \\ x = 180° - 110° \\ x = 70°$

$so \: the \: angles \: of \: a \: triangle \: are \: 44°, \: 66° ,\: 110°$

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$\huge{\mathfrak{Answer}}$