Question

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a truck of mass 1800 kg is moving with velocity 54 km per hour and deaccelerates and comes to rest after travelling 200m
calculate the force applied by brakes and work done ​

Answer 1

Answer:

Mass of the truck m = 1800 kg Initial speed u = 54 km/h = 15 m/s Final speed v = 0 s = 200 m We have v2 - u2 = 2as a = (v2 - u2)/(2s) = (0 - 152)/400 = -225/400 = - 0.56 m/s2. Retardation = 0.56 m/s2. Force applied by the brakes = Retarding force F = mass x retardation = 1800 x 0.56 = 1008 N. Work done before stopping W = Force x distance moved = 1008 x 200 = 201600 Nm = 201600

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Answer 2

Answer:

m=1800 kg

u = 54 kmph = 15 m/s

v=0

s=200 m

a=v²-u²/2s

a=0-225/400

a=-0.5625m/s²

f=ma

f=1800*-0.5625

f=1012.5 N

w=fs

w=1012.5*200

w=202500 J