Question

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Answer 1

Integration of x^3 = x^4/4
Integration of 2x^2 = 2x^3/3
$\frac{ {x}^{4} }{4} - \frac{2 {x}^{3} }{3} \\ = \frac{3 {x}^{4} - 8 {x}^{3} }{12}$
Now, we substitute the values of the limits in the equation and subtract
$\frac{3 \times {3}^{4} - 8 \times {3}^{3} }{12} - \frac{3 \times {1}^{4} - 8 \times {1}^{3} }{12} \\ = \frac{243 - 216 - 3 + 8}{12} \\ = \frac{32}{12} \\ = \frac{8}{3}$