Question

plz ise solve kr dijiye aap mahan log agar na aata ho toh spam na kare ​

Answer 1

Answer :-

◾Given :-

▪️Initial volume of solution :- 2 liter ( Water + HCl)

▪️Volume of water added :- 4 liter

▪️Initial Molarity ( M) = 6M

◾Solution :-

◾As Molarity

$= \sf{\dfrac{No. \:of \: Moles \: of\: solution}{Volume \:of\: Solution \:(in\: \it{l})}}$

◾Now as Initial Molarity was 6

$\implies \it{\dfrac{No. \:of\: Moles\: of\: solution}{2} = 6 }$

$\implies \sf{ No.\: of\: moles \:= 2 \times 6}$

$\implies \bold{ No.\:of \:moles\: = 12}$

◾Now as the No. of Moles if HCl present is 12 Moles

▪️Hence the final Molarity

$\longrightarrow \it{\dfrac{No. \: of \: moles}{Final\: volume \:of \:solution}}$

$\implies \dfrac{12}{(2+4)} = Final \: Molarity$

$\implies \dfrac{12}{6} = Final\: Molarity$

→ Final Molarity = 2 M