Plz it is urgent ....I have my classes in sometime
Answers
Answer:
In figure 1:
since YZ and XZ are equal (given in the question)
therefore ∠XYZ = ∠YXZ (opposite angles of opposite sides)
∴ ∠YXZ =70° ---------------------------------------------------1
∠XYZ +∠YZX +∠YXZ = 180° (angle sum property)
∴∠XZY = 180° -70° - 70°
= 40° ----------------------------------------------------2
∠YXZ +∠ZXV = 180° (linear angles)
70°+∠a = 180° ( from equation 1)
∠a = 110° --------------------------------------------------3
∠YZX +∠XZR = 180° (linear angles)
40° +∠b =180° ( from equation 2)
∠b = 140° --------------------------------------------------4
In figure 2:
In ΔBCD
∠B +∠C +∠D= 180° (angle sum property)
∴∠D= 68° --------------------------------------------------5
∠BDC+∠BDA = 180° (linear angle property)
∴ ∠ADB =112°
∴ ∠y =112°
sorry i was not able to solve x:(