Question

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Answer 1

Question:-

➡ Factorise 1 - 8a³

Solution:-

1 - 8a³

= (1)³ - (2a)³

= (1 - 2a)(1² + 1 × 2a + (2a)²)

= (1 - 2a)(1 + 2a + 4a²)

Hence, the factorised form is (1 - 2a)(1 + 2a + 4a²)

Identity Used:-

➡ a³ - b³ = (a - b)(a² + ab + b²)

Other Identities:-

➡ a² + 2ab + b² = (a + b)²

➡ a² - 2ab + b² = (a - b)²

➡ a² - b² = (a + b)(a - b)

➡ a³ + b³ = (a + b)(a² - ab + b²)

Answer 2

Answer:

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