plz juldi btao time ni h.
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Let's assume that
DB is a tree of height ( h ) that breaks from point A and touches the ground at point C
So, it will form a right angled triangle ABC
where B is 90° hence,
CB = 12m
AB = 9m
DA = AC. (broken part of tree)
DB = hm
Solution
we have to find out h
Now, in right angled Triangle ABC
we know that
AC² = AB² + CB².
(By Pythagoras theoram)
Putting the value of AB , AC , CB
AC² = (9)² + (12)²
AC² = 81 +144
AC² = 225
AC = 15 m
And as we have mentioned above that AC = DA
DA = 15m
Now total height of tree = DA + AB
h = 15 + 9 = 24m
Total height of tree will be 24 m
Answer = 24m
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