Question

plz koi answer de do plz​

Answer 1

Answer:

Let us first find the HCF of 210 and 55.

Applying Euclid's division lemma on 210 and 55, we get

210=55×3+45  

Since the remainder 45

=0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get

55=45×1+10  

We consider the divisor 45 and the remainder 10 and apply division lemma to get

45=4×10+5  

We consider the divisor 10 and the remainder 5 and apply division lemma  to get  

10=5×2+0  

We observe that the remainder at this stage is zero. So, that last divisor i.e.  

5 is the HCF of 210 and 55.

∴5=210×5+55y

⇒55y=5−210×5=5−1050

⇒55y=−1045

⇒y=55 −1045  =−19

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