Question

plz koi iska ans bata do bahut find kiya par nahi mila apme se koi bata do to me apka abhari rahunga aesa me nahi kahunga chup chap solve kar ke bhej do nahi to.......​

Answer 1

Its very easy, all you need to know is A³ + B³ + C³ = 3ABC when A+B+C = 0

In the given equation, taking numerator, A = a² - b² , B = b² - c², C = c² - a²

Since A + B + C =  a² - b² + b² - c² + c² - a² = 0

The numerator is 3(a² - b²)( b² - c²)( c² - a²)

Similarly, for denominator, we do the same and get 3(a-b)(b-c)(c-a)

So now dividing the above 2, we get

3(a² - b²)( b² - c²)( c² - a²) / 3(a-b)(b-c)(c-a)

(a+b)(b+c)(c+a)(a-b)(b-c)(c-a) / (a-b)(b-c)(c-a)

Here we used a²-b² = (a+b)(a-b) formula in numerator.

So, final answer is (a+b)(b+c)(c+a)

Answer 2

Step-by-step explanation:

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