plz koi solve kar do
ASAP
of class 9
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Given : O is the centre of the circle and AB is a diameter. AC is chord of circle.
To prove : ∠A = 1/2 ∠COB
Solution :
Since AO = CO ( radius of circle ), the ∆ AOC is an isosceles triangle, angle opposite to equal side will also be equal.
So,
- ∠CAO = ∠OCA
Therefore, applying exterior angle property of triangle according to which, sum of two interior angles is always equal to exterior angle.
So,
⇒ ∠CAO + ∠OCA = ∠COB
⇒ ∠CAO + ∠CAO = ∠COB
⇒ 2 ∠CAO = ∠COB
⇒ ∠CAO = 1/2 ∠COB
⇒ ∠A = 1/2 ∠COB
Hence proved.
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