plz llz solve these questions, its very imp. plzzz.....
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1
Solution 1.)
Volume = 12ky^2 + 8ky - 20k
= 4k ( 3y^2 + 2y - 5)
= 4k ( 3y^2 + 5y - 3y - 5)
=> 4k [ y(3y+5) - 1(3y+5)]
=> (4k)(3y+5)(y-1)
Dimensions are :-
Length = 4k
Width = 3y+5
Height = y-1
Solution 2.)
Let (x^2 + 1) = a
=> 4a^2 + 13a - 12
=> 4a^2 + 16a - 3a - 12
=> 4a(a+4) - 3(a+4)
=> (4a-3) (a+4)
=> (x^2 + 1 - 3) (x^2 + 1+4)
=> (x^2 - 2)(x^2 +5)
Volume = 12ky^2 + 8ky - 20k
= 4k ( 3y^2 + 2y - 5)
= 4k ( 3y^2 + 5y - 3y - 5)
=> 4k [ y(3y+5) - 1(3y+5)]
=> (4k)(3y+5)(y-1)
Dimensions are :-
Length = 4k
Width = 3y+5
Height = y-1
Solution 2.)
Let (x^2 + 1) = a
=> 4a^2 + 13a - 12
=> 4a^2 + 16a - 3a - 12
=> 4a(a+4) - 3(a+4)
=> (4a-3) (a+4)
=> (x^2 + 1 - 3) (x^2 + 1+4)
=> (x^2 - 2)(x^2 +5)
dhruvparashar875:
2nd question ka sollution?????
Answered by
0
HERE YOUR ANSWER:-
By factorizing this:
4k( 3y^2+2y-5)
Now
solve bracket by 'middle term spiliting'
4k(3y^2+5y-3y-5)
4k(3y^2-3y+5y-5)
4k[3y(y-1)+5(y-1)]
4k[(3y+5)(y-1)
(4k)(3y+5)(y-1)
WE GOT THREE TERMS.
SO,
LENGTH=4K
BREADTH=3Y+5
HEIGHT=Y-1
ANS2.
4(x^2+1)^2+13(x^2+1)-12
4(x^2+1+2x^2)+13x^2+13-12
4x^2+4+8x^2+13x^2+13-12
12x^2+13x^2+4+13-12
25x^2+4+1
25x^2+5
5(5x^2+1)
HOPE IT HELPS YOU!
༼ つ ◕_◕ ༽つ
By factorizing this:
4k( 3y^2+2y-5)
Now
solve bracket by 'middle term spiliting'
4k(3y^2+5y-3y-5)
4k(3y^2-3y+5y-5)
4k[3y(y-1)+5(y-1)]
4k[(3y+5)(y-1)
(4k)(3y+5)(y-1)
WE GOT THREE TERMS.
SO,
LENGTH=4K
BREADTH=3Y+5
HEIGHT=Y-1
ANS2.
4(x^2+1)^2+13(x^2+1)-12
4(x^2+1+2x^2)+13x^2+13-12
4x^2+4+8x^2+13x^2+13-12
12x^2+13x^2+4+13-12
25x^2+4+1
25x^2+5
5(5x^2+1)
HOPE IT HELPS YOU!
༼ つ ◕_◕ ༽つ
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