Question

plz make qno 5

you give answer with process if you don't know then not make it

Answer 1

Let the 2 vectors have magnitudes 3x and 5x respectively. Then by parallelogram law,

R² = A² + B² + 2ABcosθ

Ie,35² = (3x)² + (5x)² + 2(3x)(5x)cos60˚

ie 1225 = 9x² + 25x² + 30x²(1/2)

ie 1225 = 34x² + 15x²

ie 1225 = 49x² or x² = 25 or x = 5

So magnitude of first vector is 3x which is equal to 15N and that of the second vector is 5x which equals 25N.

Answer 2

Let us suppose the first force to be 3x and the other force to be 5x.

Now resultant can be given by sqrt [a*a + b*b + 2abcos(angle between a and b)]

So here that is, sqrt [9x*x + 25x*x + 15x*x] = 35 N

So, 7x = 35

Or, x = 5

Thus, the values of the forces are 15N and 25N.