Question

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Answer 1

Answer:

we have to put the values instead of x hpe it helps u mark it as brainliest please please

Answer 2

Answer:

$1. \: (p) = 5 - 4x + 2 {x}^{2} \\ find \: (i) \: p(0) \: \: and \: (ii) \: \: p(3)\\ putting \: x = 0 \\ 5 - 4 \times 0 + 2 \times (0) {}^{2} \\ 5 - 0 + 0 \\ = 5 \\ putting \: x = 3 \\ 5 - 4 \times 3 + 2 \times (3) {}^{2} \\ 5 - 12 + 18 \\ = 11 \\ \\ 2. \: p(y) = 4 + 3y - y {}^{2} + 5y {}^{3} \\ find \: (i) \: p(0) \: and \: p(2) \\ putting \: x = 0 \\ 4 + 3 \times 0 - (0) { }^{2} + 5 \times (0) {}^{3} \\ 4 + 0 - 0 + 0 \\ = 4 \\ putting \: x = 2 \\ 4 + 3 \times 2 - 2 { }^{2} + 5 \times 2 {}^{3} \\ 4 + 6 - 4 +5 \times 8 \\ 4 + 6 - 4 + 40 \\ 50 - 4 \\ = 46 \: \: \: answer$

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