Question

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quadratic equation​

Answer 1

2x^2 + kx + 8

For real roots D=0

b^2-4ac =0

0= k^2 - 4*2*8

0= k^2 - 64

K = 8

Answer 2

2x ² + kx + 8 =0

compare wit ax ² + bx + c =0

a=2 , b=k c=8

△ = b ² - 4ac

but △ [roots] are real and equal I.e △ =0

0 = b ² - 4ac

0= k ² - 64

64=k ²

√64 =k

8 = k

value of k is 8

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