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outermost shell of element of atomic number 105 is 5f^14,6d^3,7s^2
n+l= 8
5f =5+3=8,.14 electrons in 5f
6d=6+2=8,3 electrons in 6d
so total number of electrons =14+3=17
n+l= 8
5f =5+3=8,.14 electrons in 5f
6d=6+2=8,3 electrons in 6d
so total number of electrons =14+3=17
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