Math, asked by umang100010, 1 year ago

Plz plz answer my questions fast plz......
S is any point interior of triangle PQR, prove that PQ+PR>QS+Rs

Answers

Answered by Jiyakhera
2
I think you have an error in ur question... it should be SQ instead of PQ.. and if it is so ... .
here's ur answer...
In  triangle STR,

ST + TR > SR  …….(i)  (Sum of two sides of a triangle is greater than the third side)

In triangle PQT,

PQ + PT > QT  …..(ii)  (Sum of two sides of a triangle is greater than the third side)

Adding (i) and (ii), we get

ST + TR  + PQ + PT > SR + QT

PQ + PR + ST > SR + QS + ST  (PT + TR = PR  and QT = QS + ST)

PQ + PR > SQ + SR

Hence proved.

figure in attachment...




hope it helps. :))
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Answered by asraza812
0
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