plz plz answer these
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i)Given,
HCF is = 50
LCM is = 250
one number/2=50
one number = 100
we already know that product of two numbers = HCF×LCM
then,100×x= 50×250
x= 50×250/100
x= 5×25
x= 125
therefore the other number is 125
ii) Sum of ap
Sum= n/2[2a+(n-1)d]
3n^2-2n= n/2[2a+(n-1)d]
6n-4= 2a+(n-1)d
nth term is = 2a+(n-1)d= 6n-4
therefore 19th term is = 6×19-4
=110
therefore 19th term is 110
HOPE IT HELPS
HCF is = 50
LCM is = 250
one number/2=50
one number = 100
we already know that product of two numbers = HCF×LCM
then,100×x= 50×250
x= 50×250/100
x= 5×25
x= 125
therefore the other number is 125
ii) Sum of ap
Sum= n/2[2a+(n-1)d]
3n^2-2n= n/2[2a+(n-1)d]
6n-4= 2a+(n-1)d
nth term is = 2a+(n-1)d= 6n-4
therefore 19th term is = 6×19-4
=110
therefore 19th term is 110
HOPE IT HELPS
sanjanaojha:
bdw thanx for wishing for my exam
if i know i will compulsory answer your questions
let see ur blessing is lucky or not
ok
bdw means
follow me and then check my questions
bdw means by the way
i am seeing
bdw can i know what are you studying suryansh
ok bye talk to you later
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Hey mate here is your answer.
Marked as brainliest
Marked as brainliest
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yaah sure
again sorry suroo maine nahi dekha tha
tumhe bura laga kya ?
I know that your name is suryansh but can't I call u suroo
nice name
I think
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