plz plz answer this question fast.......
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BO = 5cm
AB = 10cm
In right angled triangle AOB
AO ^2 = AB^2 - BO^2
= 100 - 25
= 75
AO = √75
thus AC = 2 √ 75.
Now area = 1/2 AC BD.
= 10 √ 75. cm ^2.
Hope it will give you some idea. If any problem then discuss me.
Thanks
BO = 5cm
AB = 10cm
In right angled triangle AOB
AO ^2 = AB^2 - BO^2
= 100 - 25
= 75
AO = √75
thus AC = 2 √ 75.
Now area = 1/2 AC BD.
= 10 √ 75. cm ^2.
Hope it will give you some idea. If any problem then discuss me.
Thanks
Anonymous:
If you need fig. then tell me .
yes
Means you want fig....??
yess
I didn't know that there is no option to send fig . I am new here. But you draw rhombus ABCD, with AC and BD diagonals intersecting each other at O.
Hope by this you may get some idea.
Answered by
1
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