Math, asked by dhruvparashar875, 1 year ago

plz plz answer this question fast.......

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Answered by Anonymous

Here

BO = 5cm
AB = 10cm

In right angled triangle AOB

AO ^2 = AB^2 - BO^2
= 100 - 25
= 75
AO = √75
thus AC = 2 √ 75.

Now area = 1/2 AC BD.
= 10 √ 75. cm ^2.

Hope it will give you some idea. If any problem then discuss me.

Thanks

Anonymous: If you need fig. then tell me .

dhruvparashar875: yes

Anonymous: Means you want fig....??

dhruvparashar875: yess

Anonymous: I didn't know that there is no option to send fig . I am new here. But you draw rhombus ABCD, with AC and BD diagonals intersecting each other at O.

Anonymous: Hope by this you may get some idea.

Answered by SIDDH2929

Answer:

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Step-by-step explanation:

mark as brainlist answer

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